1/3 = .333…

1/3 + 1/3 + 1/3 = 3/3 = 1

.333… + 333… + 333… = .999…

.999… = 1

Discuss

  • Goddard Guryon@sopuli.xyz
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    1 year ago

    Genuinely curious about this one, what function are you assuming when using the limit approach to evaluate? I presume it is f(x) = x, but then it would not have a discontinuity at 1. Or is the point that whether 0.999… = 1 or not depends on the implicit function in the context (in which case, limits wouldn’t disprove the argument but rather add nuance to it)?